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#### TO FIND THE REVERSE OF A NUMBER IN C

Code

``````
#include<stdio.h>
int main()
{
int n,i;
int rem=0,rev=0;
int num=0;
printf("ENTER THE NUMBER ");
scanf("%d",&n);
num=n;
while(num>0)
{
rem=num%10;
rev=rev*10+rem;
num=num/10;
}
printf("THE REVERSE OF %d IS : %d",n,rev);
return 0;
}
```
```

Output

ENTER THE NUMBER 43252
THE REVERSE OF 43252 IS : 25234

What we did - Our Approach

In this problem we have to find the reverse of a number.To do so we declare a variable 'rev',which will store the result value(don't forget to initialize it with zero).

Let us consider an example :
Suppose we have to find the reverse of 235,we require three steps which needs to be performed under while loop condition (while n>0).
1 : Finding Remainder : rem=num%10
So, rem=235%10=5
2 : Finding Reverse : rev=rev*10+rem
So, rev=0+5
3 : Updating number : num=num/10;
So, num=23
But num>0, so we will perform above steps until 'num' gets equal to zero.After the last iteration we find rev=532.

See this code in :

C++

Java

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